HomeMy WebLinkAbout637 Del Guzzi Dr Technical - Building
TECHNICAL
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PLAN # 91096B-3CAR
Suntel
FOR
Home
Design
In return for payment of a one-time fee, F ~ Designs & Engineering, Inc. grants you
a limited license to use the Analysis to construct one-single house at the address shown
below.
Site Location: Lot # 5 Guzzi Drive, Port Angelos, Washington
Copyright # 8516 (please refer to this number when requesting customer support)
N OTI CE: If the Building Department accepts the Analysis without an engineer's
original "wet-stamp" seal signed with red ink or for different site location than shown above,
then it is agreed that such Building Department accepts total liability out of or in connection
with this Analysis.
CALCULATIONS VALID
WITH ORIGINAL STAMP
F Jlv"
DESIGNS & ENGINEERING, INC.
Phone: (503) 533-5100
Fax: (503) 533-5885
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Project: Lexington -3Car
File: #91096B-II0D-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet No.
1/1 S
Designs & Engineering, Inc.
-------------------------------------------------------------------------------------------------------------------------
LATERAL
ANAL YSIS
ANAL YZE BUILDING FOR ONLY WIND & SEISMIC FORCES
according to the
2003 INTERNATIONAL BUILDING CODE
WIND ANALYSIS FOR EXPOSURE "D" 110 MPH (3-sec Gust)
SEISMIC ANALYSIS FOR ZONE D2
LIABILITY LIMITATIONS
$t~ Designs & Engineering, ("FDE") was retained in a limited capacity for this project. Design is
based upon information provided by the Client, who is solely responsible for accuracy of same. No responsibility
and liability is assumed to FDE for items beyond that shown on these sheets. No constmction observations nor
soils investigations performed by FDE.
INDEMNIFICATIONS BY BUILDING DEPARTMENT
Building Department agrees to defend, indemnify and hold harmless FDE from any loss, costs, damage,
expense, including attorney fees upon trial or appeal, for liability arising out of or in connection with
FDE's Analysis unless Analysis is used for specific site location shown on cover page and contains an
oriā¬!jnal engineer's "wet-stamp" seal signed with red-ink (no photocopy allowed).
OWNERSHIP OF DOCUMENTS
,
All documents produced by FDE shall remain the property ofFDE and shall not be used unless accompanied by ar
original engineer's wet-stamp issued from FDE.
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Project: Lexington -3Car By: RF
File: #91096B-llOD-D2-WA Date: 1/2006
Designs & Engineering, Inc. Client: Suntel Home Design Job No. 2088
------------------------------------------------------------------------------------------------------------------------
Sheet No. 2/
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Sheet NO.J}
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Project: Lexington -3Car By: RF
File: #91 096B-11 OD-D2- W A Date: 1/2006
Client: Suntel Home Design Job No. 2088
------------------------------------------------------------------------------------------------------------------------
Designs & Engineering, Inc.
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1/5
Project: Lexington -3Car By: RF
File: #91096B-IIOD-D2-WA Date: l/2006
Client: Suntel Home Design Job No. 2088
------------------------------------------------------------------------------------------------------------------------
Designs & Engineering, Inc.
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Project: Lexington -3Car By: RF
File: #91096B-110D-D1-WA Date: 1/1006
Dt:signs & Engineering. Inc. Client: Suntel I-Iom~ Design Job No. 1~~_~_____________
-------------------------------------------------------------------------------------------------------
Sht:et No. ~)
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Proje:ct: Lexington -3Car
File: #91096B-II0D-D2-WA
Clie:nt: Suntel Home: Design
By: RF
Date: 1/2006
Job No. 2088
De:signs & Engineering, Inc.
She:et No. ~/;s--
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Project: Lexington -3Car
File: #91096B-IIOD-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Designs & Engineering, Inc.
Sheet No. 7/
.1/5
--------------------------------------------------------------------------------------------------------------------------
WIND ANALYSIS USING 20031Be SIMPLIFIED WIND METHOD
Data:
Y := 1.61
I := 1.0
Reference: 2003 IBC Figure 1609.6.2.1
W=TotaIWindForce=Yx Ix P x A
FRONT & REAR WALLS
Zone
Horizontal Pressure
Projected Area
A
B
C
D
Pa := 21.6 psf
Pb := 14.8 psf
Pc := 17.2 psf
Pd := 11.8 psf
Aa := 115
Ab:= 0
Ac := 490
Ad:= 0
W := Y.I.(Pa.Aa + Pb.Ab + Pc.Ac + Pd.Ad)
4
W = 1.76 x 10
Distribute wind force to roof and second-floor level:
sq. ft.
sq. ft.
sq. ft.
sq. ft.
pounds
FRwl := Y.I.(0.5.Pa.Aa + 1.0.Pb.Ab + 0.5.Pc.Ac + 1.0.Pd.Ad)
FRwl = 8.78 x 103 lbs
F2wl := Y.I.(0.5.Pa.Aa + 1.0.Pb.Ab + 0.5.Pc.Ac + 1.0.Pd.Ad)
F2wl = 8.78 x 103 lbs
SIDE WALLS
Zone
Horizontal Pressure
Projected Area
A
B
C
D
Pa := 21.6
Pb := 14.8
Pc := 17.2
Pd := 11.8
psf
psf
psf
psf
Aa := 85
Ab := 50
Ac := 895
Ad := 255
W := Y.I.(Pa.Aa + Pb.Ab + Pc.Ac + Pd.Ad)
4
W = 3.38x 10
Distribute wind force to roof and second-floor level:
sq. ft.
sq. ft.
sq. ft.
sq. ft.
pounds
4
FRw2 := Y.I.(0.15.Pa.Aa + 1.0.Pb.Ab + 0.15.Pc.Ac + 1.0.Pd.Ad) FRw2 = 1.02 x 10 lbs
F2w2 := Y.I.(0.85.Pa.Aa + O.O.Pb.Ab + 0.85.Pc.Ac + O.O.Pd.Ad)
4
F2w2 = 2.36 x 10
Ibs
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'6~
Project: Lexington -3Car
File: #91 096B-11 00-02- W A
Client: Suntel Home Design
By: RF
Date: 112006
Job No. 2088
Sheet No.8/;5
Designs & Engineering, Inc.
--------------------------------------------------------------------------------------------------------------------------
SEISMIC ANALYSIS USING 2003 IBC SIMPLIFIED ANALYSIS PROCEDURE
Data: 1=1.0 Sd:= 1.30 R:= 6.5 r := 0.45 (worst case)
E = Earthquake Base Shear = 1.2 p Qe 11.4 = 1.2 P (Sd WI 1AR)
Weights:
Roof Dead Load = 15 psf (Composition Roof Covering)
Floor Dead Load = 10 psf
Partitions = 10 psf
Extel~ior Walls + Windows = 10 psf (Average)
Mass Calculations:
Aroof := 1150 ft^2
A2ndF1oor := 950 ft^2
Al stF100r := 1800 ft^2
h2 := 21 ft
Aroofwall := 700ft^2
A2wall := 1400 ft^2
A 1 wall := 0 ft^2
hI := 10ft
Mroof := 20. Aroof + 10. Aroofwall
M2 := 20. A2ndFloor + 10. A2wall
4
Mroof = 3 x 10
4
M2 = 3.3 x 10
pounds
pounds
20
p:= 2-
r.J A2ndFloor
p := if (p < 1, 1 , p) p = 1
Sd
E := 1.2.p.-.(Mroof + M2)
lA.R
4
E = 1.08 x 10
pounds
Distribute Seismic Shears
D := Mroof.h2 + M2.hl
5
D = 9.6 x 10
FRe := Mroof. h2 . E
D
3
FRe = 7.09 x 10 pounds
F2e := M2.hl.E
D
F2e = 3.71 x 103 pounds
r
"6td1ev
Project: Lexington -3Car
File: #91096B-110D-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet No. q jls
Designs & Engineering, Inc.
--------------------------------------------------------------------------------------------------------------------------
INVESTIGATE SHEARW ALLS USING PERFORATED SHEARW ALL DESIGN APPROACH
Analyze entire brace wall line as a series of perforated shearwall panels using worst-case "maximum opening
height ratio. Individual perforated shearwall panels extend between plan discontinuity. Overturning for such
panel is calculated by rational analysis. Ref~rence Section 2305.3.7.2 - 2003IBC
Unadjusted in-plane shear force for brace wall line, FRe = 2950#
Percent full-height sheathing = 8 ft. I 16 ft = 50%
Maximum opening height ratio = 4ft 18ft = 0.50
Shear-resistance adjustment factor, Co = 0.8 (Ref: Shear-resistance adjustment factor table)
Amplified in-plane shear, V = Unadiusted shear force for brace wall line
Shear resistance adjustment factor x Total length of full-height walls
= FRe I (Co x L) = 2950# I (0.8 x 8 ft) = 460 plf
Uplift at perforated shearwall ends calculated based on rational analysis (use only 50% of weight
of first individual full-height wall segment for dead load)
2/3 average weight of full-height wall segments and portion of roof framing, W d = 110 plf
2/3 dead-load reaction at end of shearwall or comer restraint, R1 = 400#
Uplift at end of perforated shearwalls, Pu = Vfx hI - Wd x (0.5 L1) - Rl
= 460 plf x 8 ft - 110 plf x (0.5 x 4 ft) - R1 = 3100#
Uplift between wall ends, t = V- Wd = 460 plf - 110 plf= 350 plf
Wall bottom plate (11/2" thickness) to rim joist.
Use 16d common nails (0.162 by 3 1/2 inches).
Lateral resistance = 1.33 x 141# = 187# per nail
Withdrawal resistance = 1.33 x 40 pli X 2.5" = 133# per nail.
Nails for shear transfer = 460 p1f I 187# per nail = 2.4 nails per foot
Nails for uplift transfer = (460-110 pIt) I 133# per nail = 2.6 nails per foot
Net spacing for shear and uplift = 2.4" O.c.
Rim joist to wall top plate.
Use 16d common nail (0.162 by 3 1/2 in.) toe-nailed to provide shear transfer.
Lateral resistance = 0.83 x 187# per nail x 1.5 nails per ft. = 230 plf (150# per nail default maximur
for seismic loads) plus Simpson "L TP5" framing clip capacity = 630#
Net spacing for shear using LTP5 clip and 16d toenails at 8" O.c. = 630# I (460- 150#) = 24" O.c.
Transfer of uplift, t, from second floor in this example is accomplished through attachment of second floor
,wall to the continuous rim joist which has been designed to provide sufficient strength to resist the induced
moments and shears. Continuity of load path is provided by holdowns at ends of the perforated shear wall.
Use Tvpe "C" shearwall wI HTT22 holdowns, 16d at 2 1/2" o.c. sole plate nailing and LTP5 clips at 24" O.c
r
"5Jkv
Project: Lexington -3Car By: RF Sheet NO'I DJ
File: #91096B-11OD-D2- W A Date: 1/2006 lIS
~~_~~~~~_~_~_~~~1~~_~~_1~~_~~_~ ~___________~}!~_~!~_~~_~!~!}i~~~_~~_s_i_~~___________~?.~_~?_'_~_~~_~___~___________
RI ,4"'''''
"
FRe,2:15""
~OLDOUN
Pu ' 3112'12"
4'.12''' 1
P.S.W. Seqmenl
p"_~1l
1 P.S.~'5~~menl 1
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Perrordled Shedr Wd II
ELEvATION OF PERFORATED SHEARWALL
MAXiMUM OPENING ~ErGI-lT RATIO AND ~EIG'-H
WALL ~EIGI-lT
H/3 HI2 2H/3 2H/& H
8'-1Zl" 2'-8" 4/-1Zl" 5'-4" &'-8" 8'-1Zl"
Percent Full-Height Sheathing &rear. Re!i!tdnce Adju!tment. Factor
11Zl% I~ 1Zl.&':I 1Zl.53 IZlA3 1Zl.3&
21Zl% I~ 1Zl.11 a5& IZlA5 1Zl.38
31Zl% I~ 0.14 05':\ 0A':\ IZlA2
41Zl% I~ 1Zl.11 0.63 0.53 IZlA5
51Zl% I~ 0.8<Z> 0.61 0.51 1Zl51Zl
&0". I~ 0.83 0.11 0.63 0.5&
10% I~ 0.81 1Zl.11 0.6':\ 0.63
80% I~ 0.':11 0.83 1Zl.11 0.11
S~EAR RESISTANCE ADJUSTMENT FACTOR
"6~
Designs & Engineering, Inc.
Project: Lexington -3Car
File: #91 096B-11 00-02- W A
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet No. 11/
'i /5
-------------------------------------------------------------------------------------------------------------------------
INVESTIGATE UPPER-FLOOR SHEARW ALLS:
Line "A"
Rear Walls:
Line "B"
Front Walls:
Summation of full-height walls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~.100
TL
. FR
Diaghragm stress = v := 0.5.-
TL
FR
Shearwall stress = v:= 0.5.-
L
Uplift for shearwalllength = L1:= 3
(worst case)
Pu := v.8 -.5- Wd.L1 - R1
Use Type "B" Shearwall wi no hold owns
Summation of full-height walls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~.1 00
TL
Diaghragm stress = v := 0.5. FR
TL
FRe
Shearwall stress = v:== 1.1.0.5.-
(Seismic) , L "
FR
Shearwall stress = v:= 0.5.-
L
Uplift for shearwallIength = Ll:= 2
(worst case)
Pu :== v.8 -.s. Wd.Ll - Rl
Use Type "B" Shearwall wi MSTC40 holdowns
f
L := 23 ft.
TL := 35 f1.
S = 65.71 percent
v == 125.49 plf
ft.
v == 190.96 plf
Weight = Wd:= 220 plf
Rl := 660 #
Pu = 537.68
pounds
L := 15 ft.
TL := 35 ft.
S == 42.86 percent
v == 125.49 pIf
v == 259.88 plf
v = 292.81 plf
ft.
. Weight = Wd:= 160 plf
R 1 := 400 #
Pu = 1.78 x 103 pounds
1-----
~~
Designs & Engineering, Inc.
Project: Lexington -3Car
File: #91096B-IIOD-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet NO'/;lJ
//5
-----------------------------------------------------------------------------------------------------------------------
INVESTIGATE UPPER-FLOOR SHEARWALLS:
Line I Walls:
Line 2 Walls:
Summation of full-height walls lengths =
T otallength of brace wall line =
% full-height sheathing = S := ~.100
TL
D. h . FR
lag rag. m stress = v := 0.5.-
~ TL
FR
Shearwall stress = v:= 0.5.
0.84.L
Uplift for shearwalllength = L I := 8
. (worst case)
Pu:= v.8 - .5.Wd.Ll- Rl
Use Type "B" Shearwall wi MSTC40 holdowns
Summation of full-height walls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~.1 00
TL
D. hr FR
lag agm stress = v := 0.5.-
TL
FR
Shearwall stress = v:= 0.5.-
L
Uplift for shearwalllength = Ll := 27 ft.
(worst case)
Pu:= v.8 - .5.Wd.Ll- Rl
Use Type "B" Shearwall wi no holdowns
r
L := 24 ft.
TL := 27 ft.
S = 88.89 percent
v = 188.83 plf
ft.
v = 252.9 plf
Weight = Wd:= 110 plf
Rl := 400 #
3
Pu = 1.18 x 10 pounds
L := 28 ft.
TL := 28 ft.
S = 100 percent
v = 182.09 plf
v = 182.09 plf
Weight = Wd:= 110 plf
Rl := 400 #
Pu = -428.29
pounds
"6~
Project: Lexington -3Car
File: #91 096B-llOD-D2- W A
Client: Suntel Home Design
Designs & Engineering. Inc.
By: RF
Date: 1/2006
Job No. 2088
Sheet No. /.J /
1/5
-------------------------------------------------------------------------------------------------------------------------
INVESTIGATE LOWER-FLOOR SHEARWALLS:
Rear Walls:
LineA
Front Walls:
LineB
., 0.5.FRwl + 0.5.F2w1
Rlm/blockmg stress: v :=
TL
1.15.(0.5.FRe + 0.5.F2e)
L
R. /bl k' 0.5.FRw1 + 0.5.F2w1
1m oc mg stress: v :=
. TL
Seismic Shearwall 1.15.(0.5.FRe + 0.5.F2e)
v'=
stress wi wall aspect . L
ratio penalty =
Shearwall stress = v :=
Summation of full-height walls lengths =
.
T otallength of brace wall line =
% full-height sheathing = S := ~.100
TL
. F2w1
Dlaghragm stress = v := 0.2.-
~ ~ TL
Seismic Shearwall
v '=
stress wi wall aspect .
ratio penalty =
Shearwall stress = v:=
0.5. FRe + 0.5. F2e
L
L1 := 2
Uplift for sheaf\valllength =
(worst case)
Pu:= v.9 - .5.Wd.L1- R1
Type "B" Shearwall wi HTT22 holdowns
Summation of full-height walls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~. 100
TL
. F2w1
Dlaghragm stress = v:= 0.2.-
TL
0.5.FRe + 0.5.F2e
L
L1 := 2
Uplift for shearwalllength =
(worst case)
Pu := v.9 -.s. Wd.L1 - R1
L := 22 ft.
TL := 64 ft.
S = 34.38 percent
v = 27.45 plf
v = 137.25
plf
v = 282.27
plf
v = 245.45
plf
ft.
Weight = Wd:= 110 plf
R1 := 400 #
3
Pu = 1. 7 x 10
pounds
L := 16 ft.
TL := 64 ft.
S = 25 percent
v = 27.45 plf
v = 137.25
plf
v = 388.13
plf
v = 337.5
plf
ft.
Weight = Wd:= 110 plf
R1 := 400 #
3
Pu = 2.53 x 10 pounds
Use Type "C" Shearwall wi HTT22 holdowns AND Garage Frame Detail
r
.. f!J~
Designs & Engineering, Inc.
Project: Lexington -3Car
File: #91096B-IIOD-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet NO'!lfl
.1/5
-------------------------------------------------------------------------------------------------------------------------
INVESTIGATE LOWER-FLOOR SHEARW ALLS:
Line I:
Line 2:
Summation of full-height walls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~.I 00
TL
. . F2w2
Dlaghragm stress = v := 0.25.-
TL
L := 15 ft.
TL := 27 ft.
S = 55.56 percent
v = 218.33 plf
., 0.5. FRw2 + 0.25. F2w2
Rim/blockmg stress = v :=
TL
v = 407.16
plf
S.hearwall stress =
0.5.FRw2 + 0.25.F2w2
v :=
L
v = 732.89
plf
Uplift for shearwall length = LI:= 8
(worst case)
Pu:= v.9 - .5.Wd.L1- R1
Type "E" Shearwalls wi PHD6 holdo\VTIS
Summation of full-height walls lengths =
Total length of brace wall line =
% full -height sheathing = S := ~. 100
TL
. F2w2
Dlaghragm stress = v := 0.35.-
TL
ft.
Weight = Wd:= 110 plf
RI := 400 #
3
Pu = 5.76 x 10 pounds
L := 29 ft.
TL := 31 ft.
S = 93.55 percent
v = 266.22 plf
Ri ~/1...1 k' 0.5.FRw2 + 0.5.F2w2
nuu oc 'mg stress = v :=
TL
v = 544.78
plf
Shearwall stress =
0.5.FRw2 + 0.5.F2w2
v:=
L
v = 582.35
plf
Uplift for shearwalllength = L1:= 3
(worst case)
Pu := v.9 - .5. Wd.L1 - R1
Type "D" Shearwalls wi HTT22 holdowns
r
ft.
Weight = Wd:= 110 plf
R1 := 400 #
Pu = 4.68 x 103 pounds
'6~
Designs & Engineering, Inc.
Project: Lexington -3Car
File: #91096B-IIOD-D2-WA
Client: Suntel Home Design
By: RF
Date: 1/2006
Job No. 2088
Sheet No. IS- /
liS
-------------------------------------------------------------------------------------------------------------------------
INVESTIGATE LOWER-FLOOR SHEARWALLS:
Line 3:
Summation otfull-height \valls lengths =
Total length of brace wall line =
% full-height sheathing = S := ~.l 00
~ TL
. . F2w2
Dlaghragm stress = v := 0.25.-
TL
., 0.25.F2w2
Rlm/blockmg stress = v :=
TL
Shearwall stress =
0.25. F2w2
v :=
L
Uplift for shearwalllength = Ll:= 22
(worst case)
Pu:= v.9 - .5.Wd.Ll- Rl
Type "B" Shearwalls wi no holdowns
r
L := 23 ft.
TL := 23 ft.
S = 100 percent
v = 256.3 plf
v = 256.3 plf
v = 256.3
plf
ft.
Weight = Wd:= 110 plf
R 1 := 400 #
Pu = 696.67
pounds
-11
Roof Beamr 2003 International BuildinQ Code (01 NDS) 1 Ver: 6.00.8
BV: Jim Mei . Suntel Home Design on: 01-18-2006: 3:46:40 PM
Project: LEXINGTON B - Location: Beam Nr. 5 9' gargae door hdr
Summary:
5.5 IN x 11.5 IN x 9.5 FT / #2 - DouQlas Fir-Larch - Dry Use
Section Adequate By: 47.6% Controlling Factor. Section Modulus / Depth Required 9.47 In
Deflections:
Dead Load:
live Load:
Total Load:
Reactions (Each End):
live Load:
Dead Load:
Total Load:
Bearing Length Required (Beam only, support capacity not checked):
Beam Data:
Span:
Maximum Unbraced Span:
Pitch Of Roof:
Live Load Deflect. Criteria:
Total Load Deflect. Criteria:
Roof LoadinQ:
. Roof live Load-Side One:
Roof Dead Load-Side One:
Tributary Width-Side One:
Roof Live Load-Side Two:
Roof Dead Load-Side Two:
Tributary Width-Side Two:
Roof Duration Factor.
Beam Self WeiQht:
Slope/Pitch Adjusted LenQths and Loads:
Adjusted Beam Lenj:Jth:
Beam Uniform Live Load:
Beam Uniform Dead Load:
Total Uniform Load:
Properties For: #2- DouQlas Fir-Larch
BendinQ Stress:
Shear Stress:
Modulus of Elasticity:
Stress Perpendicular to Grain:
Adjusted Properties
Fb' (Tension):
Adjustment Factors: Cd=1.15 CI=1.00 Cf=1.00
DLD=
LLD=
TLD=
LL-Rxn=
DL-Rxn=
TL-Rxn=
BL=
L=
Lu=
RP=
U
U
LL1=
DL1=
TW1=
LL2=
DL2=
TW2=
Cd=
BSW=
Lad;=
wL=
wD adi=
-wT=
Fb=
Fv=
E=
Fc-perp=
Fb'=
Fv':
Fv'=
Adjustment Factors: Cd=1.15
Design Requirements:
ControllinQ Moment:
4.75 ft from left support
Critical moment created by combining all dead and live loads.
ControllinQ Shear.
At a distance d from support.
Critical shear created by combining all dead and live loads.
Comparisons With Required Sections:
Section Modulus (Moment):
Area (Shear):
Moment of Inertia (Deflection):
M=
Sreq=
S=
AreQ=
A=
Ireq=
1=
r
V=
0.05 IN
0.07 IN = U1670
0.12 IN = L/925
1603 LB
1292 LB
2895 LB
0.84 IN
9.5 FT
2.0 FT
6 : 12
360
240
25.0 PSF
17.0 PSF
12.0 FT
25.0 PSF
17.0 PSF
1.5 FT
1.15
15 PLF
9.5 FT
338 PLF
272 PLF
609 PLF
875 PSI
170 PSI
1300000 PSI
625 PSI
1005 PSI
196 PSI
6875 FT-LB
2316 LB
82.13 IN3
121.23 IN3
17.77 IN2
63.25 IN2
180.85 IN4
697.07 1N4
,-
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Root Beam[ 2003 International Building Code (01 NOS)] Ver. 6.00.8
By: Jim Mei . Suntel Home Design on: 01-18-2006
Project: LEXINGTON B - Location: Beam Nr. 5 9' gargae door hdr
Summary:
5.5 IN x 11.5 IN x 9.5 FT 1#2 - Douglas Fir-Larch - Dry Use
Section Adequate By: 47.6% Controlling Factor: Section Modulus I Depth Required 9.47 In
LOADING DIAGRAM
w
,
!'
,
Span = 9.5 ft
~
I
II
B
,
i
I
..........
A
Reactions
Live Load
A 1603 Lb
B 1603 Lb
Dead Load Total Load Uplift Load
1292 Lb 2895 Lb 0 Lb
1292 Lb 2895 Lb 0 Lb
~
Uniform Loading
Live Load Dead Load Selt Weioht Total Load
W 338 Pit 257 Pit 15 Plf 609 Pit
I